|←||101 - Splitting It Up||102 - Aces and the Joker||103 - Wood Cutouts||→|
You've scattered a deck of 52 cards and one joker facedown on a table so that you don't know which card is where.
Next you start turning the cards over one by one. Assuming that you can't flip the same card twice, what are the percentage odds that you will turn over all four aces before you turn over the joker?
Don't worry! You don't need to bother with complex calculations to solve this one!
While it may seem like you need to take other cards into account, no card in the deck, save the joker and four aces, plays any part in calculating the percentage.
Knowing that you only have to deal with five cards in your calculations, the rest is easy. You have five cards to flip, and you need one of those five cards to be last. So your answer is one out of five, or 20 percent.
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