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An ordinary analogue clock has two hands, with the longer hand moving faster around the face of the clock.
Assuming that this clock keeps perfect time, how many times will the long and short hands pass over each other between 12 noon and 12 midnight?
It's easy if you try it for real, but think carefully about the question.
The hands pass over each other 10 times. If you think about it the answer is obvious, but you might have been tricked by the question.
The hands pass over each other once an hour, but since they start and end directly on top of each other, two of the twelve hours do not count as a pass.
Why not try it on a real clock?
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