[CV067] How Many Sweets?

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066 - Five Borrowers

067 - How Many Sweets?

068 - Find the Pentagons

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How Many Sweets?
Game	Professor Layton and the Curious Village
Number	067
Type	Write Answer
Location	Clock Tower
Solved by	Professor Layton
Picarats	40
Mandatory	No
Reward	None
In other languages
Deutsch	Süßes Trio
Español	¿Cuántos caramelos?
Français	Combien de bonbons?
Italiano	Quante caramelle?
한국의	합쳐서 몇 개? (How Many?)

How Many Sweets? is a puzzle in the European version of Professor Layton and the Curious Village. For the puzzle in the American version of the game, go here.

Puzzle

Three boys are talking about how many sweets they each have.

A: B has the most!
B: If C gave me one sweet, I'd have twice as many as A does.
C: It'd be better if B gave me two sweets. Then we'd all have the same amount!

How many sweets are there in total?

Hints

• →
• Hint 1
• Hint 2
• Hint 3

Click a Tab to reveal the Hint.

If B gave C two sweets, everyone would have the same number.

This must mean that the difference between A and B is two sweets, and the difference between B and C is twice that, making four.

You know from Hint 1 that the difference between A and B is two sweets. You also know that if B got one sweet from C, he would have twice as many sweets as A.

Put these two facts together and you should be able to work out how many sweets A has.

You can work out from Hint 2 that A has three sweets.

That makes it easy to work out how many B has, since you know he has two more!

Solution

Incorrect

Too bad!

Correct

That's right! There are nine sweets in total.

The difference between the number of sweets A and B have is two. If B had one more sweet, he would have twice as many as A. Therefore, A + 3 = 2A, which means A has three sweets. B must then have five, as he has one less than twice what A has. If C had two more sweets he would have the same as A, so he must have one.