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How Many Sweets? is a puzzle in the European version of Professor Layton and the Curious Village. For the puzzle in the American version of the game, go here.

## Puzzle

Three boys are talking about how many sweets they each have.

A: B has the most!
B: If C gave me one sweet, I'd have twice as many as A does.
C: It'd be better if B gave me two sweets. Then we'd all have the same amount!

How many sweets are there in total?

## Hints

Click a Tab to reveal the Hint.

If B gave C two sweets, everyone would have the same number.

This must mean that the difference between A and B is two sweets, and the difference between B and C is twice that, making four.

You know from Hint 1 that the difference between A and B is two sweets. You also know that if B got one sweet from C, he would have twice as many sweets as A.

Put these two facts together and you should be able to work out how many sweets A has.

You can work out from Hint 2 that A has three sweets.

That makes it easy to work out how many B has, since you know he has two more!

## Solution

### Correct

That's right! There are nine sweets in total.

The difference between the number of sweets A and B have is two. If B had one more sweet, he would have twice as many as A. Therefore, A + 3 = 2A, which means A has three sweets. B must then have five, as he has one less than twice what A has. If C had two more sweets he would have the same as A, so he must have one.

A big thanks to http://professorlaytonwalkthrough.blogspot.com

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