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Aside from 28 itself, the number 28 is divisible by 1, 2, 4, 7, and 14.
When you add these numbers together, you get 1 + 2 + 4 + 7 + 14 = 28. Neat, huh! They add up to the original number.
Now for the puzzle part:
What is the smallest number for which the sum of its divisors (not including the number itself) equals the original number?
Don't be intimidated by the fact that this is a calculation problem. Just think about it for a bit. It's easier than you might expect at first.
The answer is 6.
The number 6 is divisible by 1, 2, 3, and 6, so if you don't include 6 in the sum, you get 1 + 2+ 3 = 6!
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A big thanks to http://professorlayton3walkthrough.blogspot.com