|←||078 - Lucky Tablecloth||079 - Sweet Sums||080 - Paint the Plinth||→|
- US Version
"My children have been very kind to each other lately, so I decided to give them some candy as a reward.
I have four jars of candy, A, B, C, and D. The combined number of candies in jars A and B is equal to twice the number in jar C. The combined number of candies in jars B and D equals twice the number in jar A. If you take three candies from jar D and put them in jar A, jar A will contain twice the number in jar B.
Which jar contains six pieces of candy?"
- UK Version
Below are four rather special sweetie jars, A to D.
The number of sweets in jars A and B combined is exactly twice the number of sweets in jar C. At the same time, the total number of sweets in jars B and D is twice the number of sweets in jar A, but if you move three sweets from jar D to jar A, jar A will have twice as many sweets as jar B.
One of the jars contains six sweets. Can you work out which?
Think it through and try again.
You know that A + 3 = 2B. Now, as 2B must be even and 3 is odd, A must also be odd.
A (odd) + B = 2C (even), so B = odd
B (odd) + D = 2A (even), so D = odd
The jar you are looking for contains an even number of sweets. As C is the only remaining possibility, it must be the answer by default.
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