[MM029] Tenth-Round Ace

029 - Tenth-Round Ace

Tenth-Round Ace is a puzzle in Professor Layton and the Miracle Mask.

Puzzle

US Version

A and B are confronting each other in a 10-round card game. The rules of this game are simple: fire beats wood, wood beats water, and water beats fire.

Player A drew fire three times, wood five times, and water twice, while player B drew fire twice, wood five times, and water three times. There were no ties.

Can you work out who won over 10 rounds?

UK Version

A and B are confronting each other in a ten-round card game. The rules of this game are simple: fire beats wood, wood beats water and water beats fire.

The details aren't clear, but it seems that A drew fire three times, wood five times and water twice, while B drew fire twice, wood five times and water three times. None of the rounds were drawn.

Can you work out who won this match?

Hints

Click a Tab to reveal the Hint.

The fact that there were no draws is important. It means that for every card that A drew, B drew a different card.

For instance, if A drew fire, B must have drawn wood or water. If you know how many of each type of card each player got, you should be able to calculate the win/loss ratio.

Basically, if you match up the number of one type of card that A drew with the total of the other two types that B drew, that's half the battle.

A drew wood five times. In those five rounds, B drew fire twice and water three times. From this, we can gather that A must have beaten B three times and lost twice.

US Version

You can use similar logic to determine the results of the five bouts when B drew wood. Then it's just a question of adding up all the results and working out who had the most wins.

UK Version

You can use similar logic to determine the results of the five bouts when B drew wood. Then it's just a question of adding all the results up and working out who had the most wins.

US Version

The five times that A drew wood, B drew fire twice and water three times, so A won 3-2.

The five times that B drew wood, A drew fire three times and water twice, meaning A won 3-2 again.

Now add them up. Who wins?

UK Version

The five times that A drew wood, B drew fire twice and water three times, so A won 3 - 2.

The five times that B drew wood, A drew fire three times and water twice, meaning A won 3 - 2 again.

Now add them up. Who wins?

Solution

Incorrect

Too bad.

You had a 50/50 chance of guessing correctly, but you should really think about the answer!

Correct

Correct!

US Version

If A won 3-2 when A drew wood, and A also won 3-2 when B drew wood, player A must be the overall winner.

UK Version

If A won 3 - 2 when A drew wood, and A also won 3 - 2 when B drew wood, A must be the overall winner.

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