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The Mayoral Election is a puzzle in Professor Layton and the Diabolical Box.
Puzzle
- US Version
Three people at odds with one another are running for mayor in the upcoming town election. Including these three candidates, the town has a voter population of 40 people. In order to win, a candidate must get more votes than any other candidate.
If each of the 40 voters casts a single vote and every vote is recognized, what is the fewest number of votes a candidate needs to secure victory with certainty?
- UK Version
Three people at odds with one another are running for mayor in the upcoming town election. They are all locals of the town, which has a voter population of 40. In order to win, a candidate must get more votes than any other candidate.
If each of the 40 voters casts a single vote and every vote is recognised, what is the fewest number of votes a candidate needs to secure victory?
Hints
Solution
Incorrect
Too bad!
Think hard about the clues you've been given and try again.
Correct
That's right!
- US Version
The winner has to have at least 20 votes for a certain victory. Since each of the candidates dislikes the other two, each will likely vote for themselves. Forty votes minus those three votes leaves 37 votes. The winner will need over half the votes--in this case, a minimum of 19 additional votes. Add the winning candidate's personal vote to that, and you get 20 votes. Even if another candidate gathered all the remaining 18 votes, it wouldn't be enough to overcome the candidate with 20 votes.
- UK Version
The winner needs at least 20 votes.
Since each of the candidates dislikes the other two, they will probably all vote for themselves. 40 votes minus those three votes leaves 37 votes. The winner will need over half the votes, or 19. Add the winning candidate's personal vote to that and you get 20 votes. Even if another candidate gathered all the remaining 18 votes, that wouldn't be enough to overcome the candidate with 20 votes.
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