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− | {{PuzzleNav|Cluttered Cans 2|Calendar Conundrum}} |
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− | {{PuzzleInfobox |
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− | |name={{PAGENAME}} |
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+ | |puzzle = |
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− | |imagewidth=256 |
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+ | ;US Version |
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− | |location=Layton's Challenges |
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− | |solvedby=Luke |
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− | |type=Write Answer |
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− | |obligatory=No |
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− | |picarats=60 |
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− | |extra=yes |
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− | '''{{PAGENAME}}''' is a puzzle in ''[[Professor Layton and the Unwound Future]]''. |
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Create a valid equation by placing a number (1,2 4, 5, 6, 8, 9) into each box (A, B, C, D, E, F, G). |
Create a valid equation by placing a number (1,2 4, 5, 6, 8, 9) into each box (A, B, C, D, E, F, G). |
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In this puzzle, the two digits to the left of each colon are minutes, and the two digits to the right are seconds. Sixty seconds will roll over into a minute, and you can't exceed 60 minutes. |
In this puzzle, the two digits to the left of each colon are minutes, and the two digits to the right are seconds. Sixty seconds will roll over into a minute, and you can't exceed 60 minutes. |
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+ | ;UK Version |
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+ | Create a valid equation by placing each of the numbers below into a box, A to G. |
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+ | In this puzzle, the two digits to the left of each colon are minutes and the two digits to the right are seconds. 60 seconds will roll over into a minute, but you cannot exceed 60 minutes. |
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− | ==Hints== |
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− | {{Hints |
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− | {{P}} |
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Two times three is six, so what does that tell you about what number goes in box A? |
Two times three is six, so what does that tell you about what number goes in box A? |
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+ | |hint3 = If the number in box A is greater than one, the lower value will exceed 60 minutes, which isn't allowed. Therefore, the one must go in box A. |
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+ | |hintS = Here's your last hint: |
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− | {{P}} |
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The one, four, eight, and nine all go in the top time. |
The one, four, eight, and nine all go in the top time. |
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− | {{P}} |
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− | ==Solution== |
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+ | |incorrect = Too bad! |
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− | Correct! |
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+ | Calculating time isn't quite as simple as it might seem at first. |
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+ | |correct = |
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+ | ;US Version |
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The equation 18 minutes and 49 seconds times three equals 56 minutes and 27 seconds. That wasn't to hard, right? |
The equation 18 minutes and 49 seconds times three equals 56 minutes and 27 seconds. That wasn't to hard, right? |
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Nine is the only single-digit number that will produce a seven when multiplied by three, so it's the only possible choice for box D. Also, if the number in box A was any larger than one, the answer would exceed 60 minutes, which isn't allowed in this puzzle. The rest can be calculated step by step. |
Nine is the only single-digit number that will produce a seven when multiplied by three, so it's the only possible choice for box D. Also, if the number in box A was any larger than one, the answer would exceed 60 minutes, which isn't allowed in this puzzle. The rest can be calculated step by step. |
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+ | ;UK Version |
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+ | Multiplying 18 minutes and 49 seconds by three gives 56 minutes and 27 seconds. That wasn't too hard, right? |
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+ | Nine is the only single-digit number that gives a number ending in seven when multiplied by three, so it's the only possible choice for box D. If the number in box A is any larger than one, the answer will exceed 60 minutes, which isn't allow in this puzzle. The rest can be calculated step by step. |
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− | <div align="center">[[Image:UF163S.png]]</div> |
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+ | [[File:UF163S.png|center]] |
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− | {{PuzzleIndex3}} |
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+ | |jpname = {{jpname|3倍の時間|3 bai no jikan}} |
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− | {{DEFAULTSORT:{{PAGENAME}}}} |
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+ | |dename = Drei mal drei |
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+ | |esname = Tiempo triplicado |
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+ | |frname = Temps de réflexion |
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+ | |itname = Tempo per tre |
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+ | |nlname = |
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+ | [[de:Drei mal drei]] |
Revision as of 19:53, 4 May 2019
← | 162 - Cluttered Cans 2 | 163 - Time Times Three | 164 - Calendar Conundrum | → |
Time Times Three is a puzzle in Professor Layton and the Unwound Future.
Puzzle
- US Version
Create a valid equation by placing a number (1,2 4, 5, 6, 8, 9) into each box (A, B, C, D, E, F, G).
In this puzzle, the two digits to the left of each colon are minutes, and the two digits to the right are seconds. Sixty seconds will roll over into a minute, and you can't exceed 60 minutes.
- UK Version
Create a valid equation by placing each of the numbers below into a box, A to G.
In this puzzle, the two digits to the left of each colon are minutes and the two digits to the right are seconds. 60 seconds will roll over into a minute, but you cannot exceed 60 minutes.
Hints
Solution
Incorrect
Too bad!
Calculating time isn't quite as simple as it might seem at first.
Correct
Correct!
- US Version
The equation 18 minutes and 49 seconds times three equals 56 minutes and 27 seconds. That wasn't to hard, right?
Nine is the only single-digit number that will produce a seven when multiplied by three, so it's the only possible choice for box D. Also, if the number in box A was any larger than one, the answer would exceed 60 minutes, which isn't allowed in this puzzle. The rest can be calculated step by step.
- UK Version
Multiplying 18 minutes and 49 seconds by three gives 56 minutes and 27 seconds. That wasn't too hard, right?
Nine is the only single-digit number that gives a number ending in seven when multiplied by three, so it's the only possible choice for box D. If the number in box A is any larger than one, the answer will exceed 60 minutes, which isn't allow in this puzzle. The rest can be calculated step by step.
Professor Layton and the Unwound Future | Puzzles in||
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Normal |
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Weekly | See here for weekly puzzles. | |
Hidden Door | ||
Puzzle Index: CV · DB · UF · LS · MM · AL · VS |