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|game = UF |
|game = UF |
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|number = 163 |
|number = 163 |
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+ | |puzzle = |
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+ | ;US Version |
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In this puzzle, the two digits to the left of each colon are minutes, and the two digits to the right are seconds. Sixty seconds will roll over into a minute, and you can't exceed 60 minutes. |
In this puzzle, the two digits to the left of each colon are minutes, and the two digits to the right are seconds. Sixty seconds will roll over into a minute, and you can't exceed 60 minutes. |
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+ | ;UK Version |
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+ | Create a valid equation by placing each of the numbers below into a box, A to G. |
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+ | |||
+ | In this puzzle, the two digits to the left of each colon are minutes and the two digits to the right are seconds. 60 seconds will roll over into a minute, but you cannot exceed 60 minutes. |
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+ | |hint1 = |
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+ | ;US Version |
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+ | ;UK Version |
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+ | To start with, what do you know for sure? Well, you know that the bottom time ends in seven and the top time is multiplied by three, so the number that goes in box D must end in seven when multiplied by three! There's only one that will work and it's an odd number. |
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+ | |hint2 = |
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+ | ;US Version |
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Two times three is six, so what does that tell you about what number goes in box A? |
Two times three is six, so what does that tell you about what number goes in box A? |
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+ | ;UK Version |
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+ | Nine times three gives a number ending in seven. So the nine goes in box D. |
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+ | Two times three is six, so what does that tell you about what number goes in box A? |
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+ | |hint3 = |
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+ | ;US Version |
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+ | |||
+ | If you think carefully about the rest, you should figure it out. Here's another hint, though: the five goes in box E. |
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+ | ;UK Version |
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+ | If the number in box A is greater than one, the time will exceed 60 minutes (one hour) when multiplied by three. The puzzle mentioned that 60 minutes cannot roll over into an hour so the one must go in box A. |
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+ | |||
+ | Think carefully about the rest and you should be able to work it out. Here's one more tip though: the five goes in box E. |
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+ | ;US Version |
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The one, four, eight, and nine all go in the top time. |
The one, four, eight, and nine all go in the top time. |
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The rest can be calculated from there. |
The rest can be calculated from there. |
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+ | ;UK Version |
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+ | The one, four, eight and nine all go in the top time. |
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+ | The rest can be calculated from there. |
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+ | ;US Version |
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+ | Calculating time isn't quite as simple as it might seem at first. |
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+ | ;UK Version |
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+ | Calculating time isn't quite as easy as it might seem at first. |
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+ | Correct! |
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+ | ;US Version |
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The equation 18 minutes and 49 seconds times three equals 56 minutes and 27 seconds. That wasn't to hard, right? |
The equation 18 minutes and 49 seconds times three equals 56 minutes and 27 seconds. That wasn't to hard, right? |
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Nine is the only single-digit number that will produce a seven when multiplied by three, so it's the only possible choice for box D. Also, if the number in box A was any larger than one, the answer would exceed 60 minutes, which isn't allowed in this puzzle. The rest can be calculated step by step. |
Nine is the only single-digit number that will produce a seven when multiplied by three, so it's the only possible choice for box D. Also, if the number in box A was any larger than one, the answer would exceed 60 minutes, which isn't allowed in this puzzle. The rest can be calculated step by step. |
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+ | ;UK Version |
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+ | Multiplying 18 minutes and 49 seconds by three gives 56 minutes and 27 seconds. That wasn't too hard, right? |
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+ | |||
+ | Nine is the only single-digit number that gives a number ending in seven when multiplied by three, so it's the only possible choice for box D. If the number in box A is any larger than one, the answer will exceed 60 minutes, which isn't allow in this puzzle. The rest can be calculated step by step. |
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[[File:UF163S.png|center]] |
[[File:UF163S.png|center]] |
Revision as of 02:07, 11 January 2020
← | 162 - Cluttered Cans 2 | 163 - Time Times Three | 164 - Calendar Conundrum | → |
Time Times Three is a puzzle in Professor Layton and the Unwound Future.
Puzzle
- US Version
Create a valid equation by placing a number (1,2 4, 5, 6, 8, 9) into each box (A, B, C, D, E, F, G).
In this puzzle, the two digits to the left of each colon are minutes, and the two digits to the right are seconds. Sixty seconds will roll over into a minute, and you can't exceed 60 minutes.
- UK Version
Create a valid equation by placing each of the numbers below into a box, A to G.
In this puzzle, the two digits to the left of each colon are minutes and the two digits to the right are seconds. 60 seconds will roll over into a minute, but you cannot exceed 60 minutes.
Hints
Solution
Incorrect
Too bad!
- US Version
Calculating time isn't quite as simple as it might seem at first.
- UK Version
Calculating time isn't quite as easy as it might seem at first.
Correct
Correct!
- US Version
The equation 18 minutes and 49 seconds times three equals 56 minutes and 27 seconds. That wasn't to hard, right?
Nine is the only single-digit number that will produce a seven when multiplied by three, so it's the only possible choice for box D. Also, if the number in box A was any larger than one, the answer would exceed 60 minutes, which isn't allowed in this puzzle. The rest can be calculated step by step.
- UK Version
Multiplying 18 minutes and 49 seconds by three gives 56 minutes and 27 seconds. That wasn't too hard, right?
Nine is the only single-digit number that gives a number ending in seven when multiplied by three, so it's the only possible choice for box D. If the number in box A is any larger than one, the answer will exceed 60 minutes, which isn't allow in this puzzle. The rest can be calculated step by step.
Professor Layton and the Unwound Future | Puzzles in||
---|---|---|
Normal |
| |
Weekly | See here for weekly puzzles. | |
Hidden Door | ||
Puzzle Index: CV · DB · UF · LS · MM · AL · VS |