[DB109] Walking the Dog

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108 - The Knight's Tour 3

109 - Walking the Dog

110 - Chelmey's Route

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Walking the Dog
Game	Professor Layton and the Diabolical Box
Number	109
Type	Draw Line
Location	West Y-Road
Given by	Lila
Solved by	Professor Layton
Picarats	50
Mandatory	No
Reward	Ingredient (Cinder Horse)
In other languages
日本語	犬の散歩 inu no sanpo
Deutsch	Hund auf Umwegen
Español	El paseo
Français	Sortir le chien
Italiano	In giro con il cane
한국의	강아지의 산책

Walking the Dog is a puzzle in Professor Layton and the Diabolical Box.

Puzzle

US Version

A girl takes her dog out. At first, she carries her dog for 10 seconds, but then her dad steps out. At this point, the girl sets her dog down and keeps walking. The dog immediately runs over to the dad, and upon reaching him, he turns around and runs back to the girl. The dog keeps doing this until the dad catches up with the girl.

The dog runs at five feet per second, the dad walks at two feet per second, and the girl walks at one foot per second. How far does the dog run by the time the dad catches up to his daughter.

UK Version

A young girl takes her dog out for a walk with her dad. The girl starts walking with the dog on a leash 10 seconds before the dad starts. The second the dad steps out, the girl takes the dog off the leash and the dog runs over to the dad. Upon reaching him, the dog turns around and heads for the girl. The dog keeps doing this until the dad catches up with the girl. If the dog moves at five metres per second, the father at two metres per second and the daughter at one metre per second, how far does the dog run by the time the dad catches up to his daughter?

Hints

• →
• Hint 1
• Hint 2
• Hint 3

Click a Tab to reveal the Hint.

US Version

Wordy problems like this one often have a trap buried somewhere in them. Don't get caught up in the wording.

The dad walks at two feet per second, and the daughter walks at one foot per second, so for every second that passes, the distance between the two shrinks by one foot.

UK Version

Puzzles with long explanations often have traps hidden in their phrasing. Try not to get caught out.

The dad moves at two metres per second and the daughter moves at one metre per second, so for every second that passes, the distance between the two shrinks by one metre.

US Version

The father sets out 10 seconds after his daughter. The daughter walks at a rate of one foot per second, so she's already 10 feet ahead of her father when he starts walking.

Using what you've heard from this hint and the last one, you should now know that the father catches up to his daughter in 10 seconds.

UK Version

The father sets out 10 seconds after his daughter. The daughter walks at a rate of one metre per second, so she's already 10 metres ahead of her father when he starts walking.

Using what you know from this hint and the last one, you should be able to work out that the father catches up to his daughter in 10 seconds.

US Version

The dog runs at a rate of five feet per second.

The father catches up to his daughter in exactly 10 seconds.

UK Version

The dog runs at a rate of five metres per second.

The father catches up to his daughter in exactly 10 seconds.

Solution

Incorrect

Too bad!

Are you sure you aren't overthinking this one?

Correct

Perfect!

US Version

The dog will have to run 50 feet in total.

According to the puzzle, the dog runs for the entire time it takes for the father to catch up with his daughter. Since the daughter has a 10 foot head start, and her dad gains on her at a rate of one foot per second, he'll catch up in 10 seconds. The dog is running at a rate of five feet per second so the answer must be 50 feet.

UK Version

The dog will have run 50 metres in total.

The dog runs for the entire time it takes for the father to catch up with his daughter. Since the daughter has a 10 metre head start and her dad gains on her at a rate of one metre per second, he'll catch up in 10 seconds. The dog is running at a rate of five metres per second, so the answer must be 50 metres.